2D Collision
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The normal force is the rate of change of momentum (in the direction between two centers) when two disks collide. ... The torque due to the friction will change ...
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NTNUJAVAVirtualPhysicsLaboratory»
JDK1.0.2simulations(1996-2001)»
Dynamics»
2DCollision
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Topic:2DCollision (Read520252times)
Fu-KwunHwang
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2DCollision
«on:January29,2004,05:08:42pm»
Registedusercangetfilesrelatedtothisappletforofflineaccess.Problemviewingjava?Addhttp://www.phy.ntnu.edu.tw/toexceptionsitelistIfjavaprogramdidnotshowup,pleasedownloadandinstalllatestJavaRUNTIME
Duetosomanyrequestsfromtheusers,sourcecodeforthisappletisdistributedwiththeZIPfilesyouwillreceiveifyouclickgetfileforofflineusebutton.Pleasedonotaskmetosendyouthesourcecodeagain!YouarewelcomedtocheckoutanotherCollision2DcreatedwithEJS. Pleasecheckoutlatest2DcollisioncreatedwithEJSLet'sconsidercollisionsintwodimension:PressStarttobegintheanimation.Twocircularobjectswillmovewithpre-definedvelocity(yellowarrow).Clickleftmousebuttontosuspendtheanimation.Now,youcanClicknearthetipofthevelocityvectoranddragthemousebutton left/righttochangeitsvalue(theinitialvelocityofthatobject).Clicknearthecircularboundaryanddragthemousebuttontochangeitsradius.RightClickneartheboundaryofthecircletochangeit'ssize(alsochangeit'smass,atthesametime).Clicknearthecenterofthecircleanddragthemousetochangeitslocation.Clickthemousebuttonagaintoresumetheanimation.Whenthetwoobjectscollide,theanimationwillbesuspend.Pressthemousebutton(Donotreleaseit)toseethevelocityvectorsjustafterthecollision.PressResetbuttontoresetparameterstodefaultvalues.etaisthecoefficientofrestitutioneatVf/ViVf=relativevelocityjustaftercollision Vi=relativevelocityjustbeforecollision forelasticcollisioneta=1. forperfectlyinelasticcollisioneta=0.Youcanselectdifferentframeofreferencetoviewtherelativemotionofalltheobjects.labisalaboratoryinertialframe.m1,m2andCMareframeofreferencewithrespecttoleftcircularobjectm1,rightcircularobjectm2andcenterofmassform1andm2.Viewcollisionin1dimension.Atthemomentwhentheycollide,theforcebetweenthetwocircleobjectsisalongthelinewhichconnectthecenterofthetwoobjects.Nowwehave1-Dcollisionproblem:twoobjectmoveinthedirectionalongthelineconnectbetweentheircenter,withvelocitysalongthisdirections.(Redvectors)Thevectorperpendiculartotheabovecomponents(greenvectors)willnotchangedaftercollision.(Ifthereisnofrictionforcebetweenthetwoobjects)PleasecheckoutRigidBodyCollisionsfor2Dcollisionbetweenrectangleshapeobjects.Registedusercangetfilesrelatedtothisappletforofflineaccess.Problemviewingjava?Addhttp://www.phy.ntnu.edu.tw/toexceptionsitelistIfjavaprogramdidnotshowup,pleasedownloadandinstalllatestJavaRUNTIME
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Fu-KwunHwang
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Howtoconvert2Dcollisioninto1D
«Reply#1on:October28,2004,03:19:44pm»
[img:53443ef2ad]http://www.phy.ntnu.edu.tw/demolab/phpBB/pics/2_2_collision2d.png[/img:53443ef2ad]1.Findthetimewhentwoballcollide:D=R1+R2 whereD=Distancebetweencenteroftwoballs,andR1/R2isradiusofeachballs2.Findthelineconnectcenteroftwoballs.andcalculatethecomponentofthevelocitryforeachballalonethelineconnectthosetwoballs. Forexample:VelocityforeachballisVaandVb(beforecollision) CalculateVapandVbp.(andanothernormalcomponentVan,Vbn)3.Itisbecomea1Dcollisionproblem:ballAwithvelocityVapcollidewithballBwithvelocityVbp.Youshouldbeabletocalculatevelocityaftercollisionforeachball. forexample: Vap2=((m1-m2)/(m1+m2))vap+(2m2/(m1+m2))Vbpand Vbp2=(2m1/(m1+m2))Vap+((m2-m1)/(m2+m1))Vbp ThetangentialcomponentisnotchangedVan2=Van,andVbn2=Vbn4.Calculatethevectorsumforvelocityofeachballaftercollision Va2=Vap2+Van2andVb2=Vb2p+Vbn2(vectorsummation)
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siput_tiung
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topic4
«Reply#2on:March12,2005,12:41:59pm»
hi,isthereanydifferencebetweenballsorhumanswhencollisionoccur?iamtryingtowriteahumanmodelforcollisioncases...andstilltryingvery2hardtomakeitinrealisticway.yourappletseemslikegoodformeandi'mimpressedwithit...perhapsitwouldbegoodtobeappliedtomyproject..canuexplainitindetailhow'sthecalculationforit?dividingitinto3condition,(1.before,2.during..,3.after..)wouldbereally2great...thanks..ref:http://www.phy.ntnu.edu.tw/ntnujava/viewtopic.php?t=19Regards,[email protected]
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Fu-KwunHwang
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topic4
«Reply#3on:March12,2005,03:20:41pm»
Theabovecalculationassumeitisanelasticcollisionbetweentwoballs.i.e.Noenergyislossduringthecollision.Andtheballwouldnotchangeshape.Forcollisionbetwentwohuman,wewillchangeourbodymovment.Wouldyouexplaininmoredetailwhyyouneedtocalculatecollisionbetweenhuman?Whiletwopersonsarewalkingor...?
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siput_tiung
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topic4
«Reply#4on:March14,2005,11:07:58am»
let'ssee...herei'mtryingtodocollisionavoidanceamonghuman...forexample...humanAistryingtogotopoint1...andifthereisanotherhumanblockinghisway...then..thehumanAmustavoidit..bychangingtootherdirectionandthen,gotopoint1..here...icandetectthecollisionifthereishumanblockinganotherhuman..but,ihaveproblemwithchangingdirection...tomakeitrealistic..
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Fu-KwunHwang
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topic4
«Reply#5on:March14,2005,03:33:38pm»
Becauseyouwanttoavoidcollisionamonghuman.Sothereisnocollisionamonghuman.Youcancheckthevelocityvector,ifitispointingtoanotherperson.Thensomeoneisblockinghisway.Providethehorizontaldisplayment,youcancalculatetheleastchangeofthevelocity.Thepersoncanchangedirectionrightatthatpointorchangevelocitygradually.
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siput_tiung
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topic4
«Reply#6on:March16,2005,03:41:52pm»
thanks..igottheideanow..
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Fu-KwunHwang
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JavaCodeforcollisionin2D
«Reply#7on:May11,2005,08:03:51am»
Duetosomanyemailquestionsaskingforhelp.Ire-wrotethisposttoincludemoredetailcalculationsteps:Assumetheradiusfortwoballarer1andr2,andthecoordinatesare(x1,y1)and(x2,y2).Usually,wecalculatethedistancebetweentwoballsd=sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));Thecollisionshouldhaveoccurredifdequalr1+r2;//if(d==r1+r2)However,thereisafinitetimestepdtinthesimulationcalculation,somostoftenwewouldnotbeabletofindtheabovecondition(exacttimewhentwoballrealoccurred).Sowecheckifd<=r1+r2;Thenweknowthecollisionshouldhaveoccurred.Therealcollisionshouldhaveoccurredbeforeyoudetectedthatthedistancebetweentwocenteroftheballsdislessthanthesumofthosetwoballsr1+r2.(d
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